Question

in a group of koi fish, some individuals have red eyes and others have black eyes. in this group, the gene for the eye color trait has two alleles. the allele for black eyes (e) is recessive to the allele for red eyes (e). this punnett square shows a cross between two koi fish. punnett square with rows e, e and columns e, e; cells ee, ee, ee, ee what is the probability that a koi fish produced by this cross will be homozygous dominant for the eye color gene? %

Explanation:

Step1: Identify homozygous dominant

Homozygous dominant is \( EE \). Count cells with \( EE \) in Punnett square.

Step2: Count total cells

Total cells in Punnett square: \( 4 \) (EE, Ee, Ee, ee).

Step3: Calculate probability

Number of \( EE \) cells: \( 1 \). Probability \( = \frac{1}{4} = 0.25 \). Convert to percentage: \( 0.25 \times 100 = 25\% \).

Answer:

25