Question

graph the solution set for $n - 8leq - 4$ or $\frac{3}{4}n < - 6$. select
o solution\ if applicable.

Explanation:

Step1: Solve the first inequality

Add 8 to both sides of $n - 8\leq - 4$.
$n-8 + 8\leq-4 + 8$
$n\leq4$

Step2: Solve the second inequality

Multiply both sides of $\frac{3}{4}n<-6$ by $\frac{4}{3}$. Since $\frac{4}{3}>0$, the inequality sign remains the same.
$n<-6\times\frac{4}{3}$
$n < - 8$

Step3: Analyze the "or" condition

The solution of $n\leq4$ or $n < - 8$ is $n\leq4$. On the number - line, we shade all the numbers to the left of and including 4. We use a closed circle at 4 (because $n$ can equal 4) and an arrow pointing to the left.

Answer:

Shade the number - line to the left of and including 4, with a closed circle at 4.