Question

graph the solution set for (m - 8leq - 6) and (\frac{3}{4}m < - 3). select
o solution\ if applicable.

Explanation:

Step1: Solve the first inequality

Add 8 to both sides of $m - 8\leq - 6$.
$m-8 + 8\leq - 6+8$
$m\leq2$

Step2: Solve the second inequality

Multiply both sides of $\frac{3}{4}m\lt - 3$ by $\frac{4}{3}$.
$m\lt - 3\times\frac{4}{3}$
$m\lt - 4$

Step3: Find the intersection

The solution of the compound - inequality "and" is the intersection of the two solution sets. Since $m\leq2$ and $m\lt - 4$, the overall solution is $m\lt - 4$.
To graph:

1. Draw a number line.
2. Place an open circle at $m=-4$ (because the inequality is $m\lt - 4$, not $m\leq - 4$).
3. Shade the part of the number line to the left of $m = - 4$.

Answer:

Graph: Place an open circle at - 4 and shade to the left on the number line.