Question

graph the solution set for n - 8 ≤ -4 and $\frac{3}{4}n < -6$. select
o solution\ if applicable.

Explanation:

Step1: Solve the first inequality

Add 8 to both sides of $n - 8\leq - 4$.
$n-8 + 8\leq-4 + 8$
$n\leq4$

Step2: Solve the second inequality

Multiply both sides of $\frac{3}{4}n<-6$ by $\frac{4}{3}$.
$n<-6\times\frac{4}{3}$
$n < - 8$

Step3: Find the intersection

We need to find values of $n$ that satisfy both $n\leq4$ and $n < - 8$. The intersection of these two inequalities is $n < - 8$.
On the number - line, we draw an open circle at - 8 (since $n$ is strictly less than - 8) and shade to the left.

Answer:

We draw an open circle at - 8 and shade the part of the number - line to the left of - 8.