the graph shows how the strength of the earths gravitational field varies as the distance from the earths surface increases.which row describes the effect that this has on the mass and on the weight of an object as it moves further away from the earths surface?a measuring cylinder contains 40 cm³ of water.a solid metal ball is dropped into the water and the water level rises to 56 cm³.the mass of the ball is 80 g.what is the density of the metal from which the ball is made?a 0.20 g/cm³ b 1.4 g/cm³ c 2.0 g/cm³ d 5.0 g/cm³a car travels along a horizontal road at constant speed. three horizontal forces act on the car.the diagram shows two of these forces.what is the size and the direction of the third horizontal force acting on the car?a 1200 n backwards b 1200 n forwards c 1800 n backwards d 1800 n forwardsthe gravitational field strength on the moon is less than on the earth.which of these is different when done on the moon compared with when done on the earth?a the gravitational potential energy gained by a stone lifted through the same vertical height b the kinetic energy gained by a ball when hit with the same force for the same period of time c the momentum gained by a bullet when fired from the same gun d the work done in accelerating a stone from rest to the same speedthe mass of a full bottle of cooking oil is 1.30 kg.when exactly half of the oil has been used, the mass of the bottle plus the remaining oil is 0.90 kg.what is the mass of the empty bottle?a 0.40 kg b 0.50 kg c 0.65 kg d 0.80 kga solid ball has a volume of 4.0 cm³. the density of the ball is 1.6 g/cm³.what is the mass of the ball?a 0.4 g b 2.5 g c 4.0 g d 6.4 g

Question

Accepted Answer

### Question 4
# Explanation:
## Step1: Calculate the volume of the metal ball
The volume of the metal ball $V$ is the change in water level. $V = 56\space cm^{3}-40\space cm^{3}=16\space cm^{3}$
## Step2: Use the density formula $
ho=\frac{m}{V}$
Given $m = 80g$ and $V = 16\space cm^{3}$, then $
ho=\frac{80g}{16\space cm^{3}} = 5.0g/cm^{3}$

# Answer:
D

### Question 5
# Explanation:
## Step1: Analyze the forces in the horizontal direction
Since the car is moving at a constant speed, the net force $F_{net}=0$. Let the force from the engine be $F_{engine}=1500N$, air - resistance $F_{air}=300N$. Let the third force be $F_{3}$
## Step2: Apply the equilibrium condition $F_{net}=F_{engine}-F_{air}-F_{3}=0$
$F_{3}=F_{engine}-F_{air}$. Substitute $F_{engine} = 1500N$ and $F_{air}=300N$, we get $F_{3}=1200N$ in the backward direction (opposite to the direction of motion to balance the forces)

# Answer:
A

### Question 6
# Explanation:
## Step1: Recall the formula for gravitational potential energy $U = mgh$
Since $g_{moon}<g_{earth}$ and $m$ (mass of the stone) and $h$ (height) are the same. For option A, $U_{moon}=mg_{moon}h$ and $U_{earth}=mg_{earth}h$, so $U_{moon}<U_{earth}$
## Step2: Recall the impulse - momentum theorem $I = F\Delta t=\Delta p$ (for option C) and work - energy theorem $W=\Delta K=\frac{1}{2}mv^{2}$ (for option D)
For option B, using $F = ma$ and $v = u+at$ ($u = 0$), $v=\frac{F}{m}t$, $K=\frac{1}{2}mv^{2}=\frac{F^{2}t^{2}}{2m}$ (independent of $g$). For option C, $p = mv$, from $F = ma$ and $v = u + at$ ($u=0$), $v=\frac{F}{m}t$, $p=\frac{Ft}{1}$ (independent of $g$). For option D, $W=\frac{1}{2}mv^{2}$ (independent of $g$)

# Answer:
A

### Question 7
# Explanation:
## Step1: Let the mass of the bottle be $m_{b}$ and the mass of the full - oil be $m_{o}$
We know $m_{b}+m_{o}=1.30kg$ and $m_{b}+\frac{m_{o}}{2}=0.90kg$
## Step2: Subtract the second equation from the first equation
$(m_{b}+m_{o})-(m_{b}+\frac{m_{o}}{2})=1.30 - 0.90$
$\frac{m_{o}}{2}=0.40kg$, then $m_{o}=0.80kg$
## Step3: Substitute $m_{o}$ into $m_{b}+m_{o}=1.30kg$
$m_{b}=1.30 - 0.80=0.50kg$

# Answer:
B

### Question 8
# Explanation:
## Step1: Use the density formula $
ho=\frac{m}{V}$
Given $
ho = 1.6g/cm^{3}$ and $V = 4.0cm^{3}$
## Step2: Solve for $m$
$m=
ho V$, substitute the values: $m=1.6g/cm^{3}\times4.0cm^{3}=6.4g$

# Answer:
D

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QUESTION IMAGE

Question

Explanation:

Question 4

Step1: Calculate the volume of the metal ball

Step2: Use the density formula \(

Step1: Analyze the forces in the horizontal direction

Step2: Apply the equilibrium condition \(F_{net}=F_{engine}-F_{air}-F_{3}=0\)

Step1: Recall the formula for gravitational potential energy \(U = mgh\)

Step2: Recall the impulse - momentum theorem \(I = F\Delta t=\Delta p\) (for option C) and work - energy theorem \(W=\Delta K=\frac{1}{2}mv^{2}\) (for option D)

Answer:

Question 5