Question

graph the line with the equation $y = -3x + 3$.

Explanation:

Step1: Find the y - intercept

The equation is in slope - intercept form \(y = mx + b\), where \(b\) is the y - intercept. For \(y=-3x + 3\), when \(x = 0\), \(y=3\). So the point \((0,3)\) is on the line.

Step2: Find the x - intercept

Set \(y = 0\). Then \(0=-3x + 3\). Solve for \(x\):
\(3x=3\), so \(x = 1\). The point \((1,0)\) is on the line.

Step3: Plot the points and draw the line

Plot the points \((0,3)\) and \((1,0)\) on the coordinate plane. Then draw a straight line passing through these two points.

Answer:

Plot the points \((0,3)\) (y - intercept) and \((1,0)\) (x - intercept) and draw a straight line through them to graph \(y=-3x + 3\).