Question

graph the image of trapezoid stuv after the following glide reflection:
translation 15 units down
reflection across the y - axis

Explanation:

Step1: Find coordinates of original points

Assume \( S(-14,12)\), \(T(-10,10)\), \(U(-10,6)\), \(V(-14,2)\)

Step2: Translate 15 units down

Use the rule \((x,y)\to(x,y - 15)\)

• \(S(-14,12)\to S'(-14,12-15)=(-14,-3)\)
• \(T(-10,10)\to T'(-10,10 - 15)=(-10,-5)\)
• \(U(-10,6)\to U'(-10,6-15)=(-10,-9)\)
• \(V(-14,2)\to V'(-14,2-15)=(-14,-13)\)

Step3: Reflect across the \(y\) - axis

Use the rule \((x,y)\to(-x,y)\)

• \(S'(-14,-3)\to S''(14,-3)\)
• \(T'(-10,-5)\to T''(10,-5)\)
• \(U'(-10,-9)\to U''(10,-9)\)
• \(V'(-14,-13)\to V''(14,-13)\)

Answer:

Plot the points \(S''(14,-3)\), \(T''(10,-5)\), \(U''(10,-9)\), \(V''(14,-13)\) and connect them to form the image of the trapezoid after the glide reflection.