Question

graph the image of square bcde after a translation 5 units left and 8 units down.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated 5 units left and 8 units down, the new - point is $(x - 5,y - 8)$.

Step2: Identify original coordinates

Assume the coordinates of the vertices of square $BCDE$ are $B(-2,1)$, $C(7,1)$, $D(7,9)$, $E(-2,9)$.

Step3: Apply translation to point B

For point $B(-2,1)$: $x=-2,y = 1$. New $x=-2-5=-7$, new $y=1 - 8=-7$. So the new - point $B'$ is $(-7,-7)$.

Step4: Apply translation to point C

For point $C(7,1)$: $x = 7,y = 1$. New $x=7-5 = 2$, new $y=1 - 8=-7$. So the new - point $C'$ is $(2,-7)$.

Step5: Apply translation to point D

For point $D(7,9)$: $x = 7,y = 9$. New $x=7-5 = 2$, new $y=9 - 8 = 1$. So the new - point $D'$ is $(2,1)$.

Step6: Apply translation to point E

For point $E(-2,9)$: $x=-2,y = 9$. New $x=-2-5=-7$, new $y=9 - 8 = 1$. So the new - point $E'$ is $(-7,1)$.

Step7: Graph the new square

Plot the points $B'(-7,-7)$, $C'(2,-7)$, $D'(2,1)$, $E'(-7,1)$ on the coordinate - plane and connect them to form the new square.

Answer:

Graph the square with vertices $(-7,-7)$, $(2,-7)$, $(2,1)$, $(-7,1)$.