Question

graph the image of parallelogram bcde after a reflection over the y - axis.

Explanation:

Step1: Find coordinates of original points

Assume coordinates from graph: \(B(-8,-7)\), \(C(-8,-5)\), \(D(-3,-2)\), \(E(-3,-4)\)

Step2: Apply reflection over \(y\)-axis formula \((x,y)\to(-x,y)\)

For \(B(-8,-7)\): \((-8,-7)\to(8,-7)\)
For \(C(-8,-5)\): \((-8,-5)\to(8,-5)\)
For \(D(-3,-2)\): \((-3,-2)\to(3,-2)\)
For \(E(-3,-4)\): \((-3,-4)\to(3,-4)\)

Step3: Plot new points and connect

Plot \((8,-7)\), \((8,-5)\), \((3,-2)\), \((3,-4)\) and connect to form parallelogram.

Answer:

Plot the points \((8,-7)\), \((8,-5)\), \((3,-2)\), \((3,-4)\) on the coordinate plane and connect them in order to get the reflected parallelogram.