Question

graph the image of δcde after a reflection over the y-axis.

Explanation:

Step1: Find coordinates of C, D, E

From the graph:

• \( C(-8, 3) \)
• \( D(-8, 5) \)
• \( E(-6, 2) \)

Step2: Apply reflection over y - axis

The rule for reflection over the \( y \)-axis is \( (x,y)\to(-x,y) \).

• For \( C(-8, 3) \): New coordinate \( C'(8, 3) \) (since \( -(-8)=8 \), \( y = 3 \) remains)
• For \( D(-8, 5) \): New coordinate \( D'(8, 5) \) (since \( -(-8)=8 \), \( y = 5 \) remains)
• For \( E(-6, 2) \): New coordinate \( E'(6, 2) \) (since \( -(-6)=6 \), \( y = 2 \) remains)

Step3: Plot the new points

Plot \( C'(8, 3) \), \( D'(8, 5) \), and \( E'(6, 2) \) on the coordinate plane and connect them to form the reflected triangle \( \triangle C'D'E' \).

Answer:

The image of \( \triangle CDE \) after reflection over the \( y \)-axis has vertices at \( C'(8, 3) \), \( D'(8, 5) \), and \( E'(6, 2) \). (To graph, plot these points and connect them.)