Question

graph the image of $\triangle klm$ after a dilation with a scale factor of 3, centered at the origin.

Explanation:

Step1: Identify original coordinates

From graph: $K(-3,0)$, $L(-3,3)$, $M(2,-2)$

Step2: Apply dilation rule

Dilation center origin, scale 3: $(x,y)\to(3x,3y)$
$K'=3*(-3,0)=(-9,0)$
$L'=3*(-3,3)=(-9,9)$
$M'=3*(2,-2)=(6,-6)$

Step3: Plot image triangle

Connect $K'(-9,0)$, $L'(-9,9)$, $M'(6,-6)$

Answer:

The image triangle $\Delta K'L'M'$ has vertices at $(-9,0)$, $(-9,9)$, and $(6,-6)$ (plot these points and connect them on the grid).