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graph the function. \ (x) = \\begin{cases} -x^2 + 1 & \\text{for } x \\…

Question

graph the function.

\
(x) = \

$$\begin{cases} -x^2 + 1 & \\text{for } x \\le 1 \\\\ 5x - 5 & \\text{for } x > 1 \\end{cases}$$

\\

part 1 of 5
the first rule defines a parabola with vertex \\((0, 1)\\).

part 2 of 5
since \\(x \le 1\\), the select point \\((\quad, \quad)\\) is graphed as a solid dot.

Explanation:

Identify the boundary point for the first rule

Using the Piecewise Functions and Ordered Pairs knowledge points

$$ LATEXBLOCK0 $$

Determine the endpoint style

Using the Piecewise Functions knowledge point

$$ LATEXBLOCK1 $$

Answer:

Since \(x \le 1\), the <blank>endpoint</blank> point <blank>\((1, 0)\)</blank> is graphed as a solid dot.