Question

graph the compound inequality on the number line.
$x\geq -4$ and $x < 1$

Explanation:

Step1: Graph \(x\geq - 4\)

For \(x\geq - 4\), we use a closed - circle at \(x = - 4\) (because the inequality includes equality) and draw an arrow to the right.

Step2: Graph \(x\lt1\)

For \(x\lt1\), we use an open - circle at \(x = 1\) (because the inequality does not include equality) and draw an arrow to the left.

Step3: Find the intersection

The compound inequality \(x\geq - 4\) and \(x\lt1\) means we take the overlapping region of the two graphs.

Answer:

We have a closed - circle at \(-4\), an open - circle at \(1\), and the line segment connecting them on the number line.