Question

glycolysis is the first step in cellular respiration. which option best summarizes the process? (1 point) ○ anaerobic; 6-carbon glucose forms two 3-carbon adp; forms a net total of 4 atp ○ aerobic; 6-carbon glucose forms three 2-carbon pyruvates; forms a net total of 2 atp ○ anaerobic; 6-carbon glucose forms two 3-carbon pyruvates; forms a net total of 2 atp ○ aerobic; 6-carbon glucose forms four 3-carbon adp; forms a net total of 3 atp

Explanation:

1. Recall the key facts about glycolysis:

• Glycolysis is an anaerobic process (does not require oxygen).
• A 6 - carbon glucose molecule is broken down into two 3 - carbon pyruvate molecules.
• The net production of ATP in glycolysis is 2 ATP (2 ATP are used in the initial steps and 4 are produced, so 4 - 2 = 2 net ATP).

1. Analyze each option:

• Option 1: Incorrect. Glycolysis produces pyruvate, not ADP, and the net ATP is 2, not 4.
• Option 2: Incorrect. Glycolysis is anaerobic, and it produces two 3 - carbon pyruvates, not three 2 - carbon pyruvates.
• Option 3: Correct. It matches the facts: anaerobic, 6 - carbon glucose forms two 3 - carbon pyruvates, and net 2 ATP.
• Option 4: Incorrect. Glycolysis is anaerobic, produces pyruvate (not ADP), and the net ATP and the number of products are wrong.

Answer:

C. anaerobic; 6 - carbon glucose forms two 3 - carbon pyruvates; forms a net total of 2 ATP (assuming the third option is labeled C, if the original options were labeled with letters like A, B, C, D, and the third option is the correct one with the described content)