Question

given \\(\overline{bcd}\\), use the protractor to measure \\(\angle bce\\) and \\(\angle dce\\). also determine the sum of two angle measurements.

move the protractor using the central blue dot.
rotate / scale the protractor using the green dot.
you may shift or zoom the canvas using your mouse.

answer attempt 1 out of 2
\\(\text{m}\angle bce = \square^\circ\\) \\(\text{m}\angle dce = \square^\circ\\)
\\(\text{m}\angle bce + \text{m}\angle dce = \square^\circ\\)

Explanation:

Step1: Measure ∠BCE

Place the protractor's center at point C, align one side (BC) with the protractor's base. The ray CE intersects the protractor at 70°, so \( m\angle BCE = 70^\circ \).

Step2: Measure ∠DCE

Since BCD is a straight line (180°), and \( \angle BCE = 70^\circ \), \( m\angle DCE = 180^\circ - 70^\circ = 110^\circ \).

Step3: Sum the angles

Add the two angle measures: \( 70^\circ + 110^\circ = 180^\circ \).

Answer:

\( m\angle BCE = \boxed{70}^\circ \), \( m\angle DCE = \boxed{110}^\circ \), \( m\angle BCE + m\angle DCE = \boxed{180}^\circ \)