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Question
given: w || x and y is a transversal. prove: ∠3 and ∠5 are supplementary. use the drop - down menus to complete the proof. given that w || x and y is a transversal, we know that ∠1 ≅∠5 by the. therefore, m∠1 = m∠5 by the definition of congruent. we also know that, by definition, ∠3 and ∠1 are a linear pair so they are supplementary by the. by the, m∠3 + m∠1 =. congruent supplements theorem, definition of a linear pair, definition of supplementary angles, linear pair postulate
Step1: Identify angle - congruence reason
Since \(w\parallel x\) and \(y\) is a transversal, \(\angle1\cong\angle5\) by the corresponding - angles postulate.
Step2: Identify linear - pair property
\(\angle3\) and \(\angle1\) are a linear pair. They are supplementary by the linear - pair postulate.
Step3: Substitute and conclude
By the substitution property, since \(m\angle1 = m\angle5\), we can substitute \(m\angle1\) with \(m\angle5\) in \(m\angle3 + m\angle1=180^{\circ}\) to get \(m\angle3 + m\angle5 = 180^{\circ}\), so \(\angle3\) and \(\angle5\) are supplementary by the definition of supplementary angles.
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- corresponding - angles postulate
- linear - pair postulate
- substitution property