Question

given a standardized normal distribution, what is the probability that z is greater than 1.64
0.0329
0.9671
0.9329
0.0505

Explanation:

Step1: Use the property of standard normal distribution

For a standard normal distribution \(Z\), \(P(Z > z)=1 - P(Z\leq z)\). Here \(z = 1.46\).

Step2: Look up the value in the standard normal table

From the standard - normal table (z - table), \(P(Z\leq1.46)=0.9279\). Then \(P(Z > 1.46)=1 - 0.9279 = 0.0721\) (This is wrong for the wrong \(z\) value. Let's correct for \(z = 1.84\)).
If \(z = 1.84\), from the standard - normal table \(P(Z\leq1.84)=0.9671\). Then \(P(Z>1.84)=1 - P(Z\leq1.84)\).

Answer:

0.0329