Question

given right triangle pqr, which represents the value of sin(p)? options: \\(\frac{rp}{rq}\\), \\(\frac{rp}{pq}\\), \\(\frac{rq}{pq}\\), \\(\frac{rq}{pr}\\)

Explanation:

Step1: Recall the sine formula

In a right - triangle, \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\).

Step2: Identify the sides for \(\angle P\)

For \(\angle P\) in right - triangle \(PQR\) with \(\angle R = 90^{\circ}\), the side opposite to \(\angle P\) is \(RQ\), and the hypotenuse is \(PQ\).

Answer:

\(\frac{RQ}{PQ}\)