QUESTION IMAGE
Question
given that the point (80, -84) is on the terminal side of an angle, θ, find the exact value of the following:
sin(θ)=
cos(θ)=
tan(θ)=
csc(θ)=
sec(θ)=
cot(θ)=
question help: worked example 1
Step1: Calculate the radius \(r\)
Use the formula \(r=\sqrt{x^{2}+y^{2}}\), where \(x = 80\) and \(y=-84\).
Step2: Calculate \(\sin(\theta)\)
Use the formula \(\sin(\theta)=\frac{y}{r}\), where \(y=-84\) and \(r = 116\).
Step3: Calculate \(\cos(\theta)\)
Use the formula \(\cos(\theta)=\frac{x}{r}\), where \(x = 80\) and \(r = 116\).
Step4: Calculate \(\tan(\theta)\)
Use the formula \(\tan(\theta)=\frac{y}{x}\), where \(x = 80\) and \(y=-84\).
Step5: Calculate \(\csc(\theta)\)
Use the formula \(\csc(\theta)=\frac{r}{y}\), where \(y=-84\) and \(r = 116\).
Step6: Calculate \(\sec(\theta)\)
Use the formula \(\sec(\theta)=\frac{r}{x}\), where \(x = 80\) and \(r = 116\).
Step7: Calculate \(\cot(\theta)\)
Use the formula \(\cot(\theta)=\frac{x}{y}\), where \(x = 80\) and \(y=-84\).
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\(\sin(\theta)=-\frac{21}{29}\)
\(\cos(\theta)=\frac{20}{29}\)
\(\tan(\theta)=-\frac{21}{20}\)
\(\csc(\theta)=-\frac{29}{21}\)
\(\sec(\theta)=\frac{29}{20}\)
\(\cot(\theta)=-\frac{20}{21}\)