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given the parallel lines cut by a transversal below, what type of angle…

Question

given the parallel lines cut by a transversal below, what type of angle pair is the given angle and x, and what is the measure of x? angle pair is degrees

Explanation:

Step1: Identify the angle pair

When two parallel lines are cut by a transversal, the \(127^{\circ}\) angle and \(x\) are same - side interior angles. But wait, no! Wait, actually, looking at their positions, they are actually alternate interior angles. Wait, no, wait, no - the \(127^{\circ}\) angle and \(x\) are supplementary because they are same - side interior angles. Wait, no, hold on. Wait, no, actually, the \(127^{\circ}\) angle and \(x\) are same - side interior angles. But wait, no! Wait, the \(127^{\circ}\) angle and its adjacent angle (on the same line) is \(180 - 127=53^{\circ}\). But no, wait, actually, when two parallel lines \(a\) and \(b\) are cut by transversal \(t\), the \(127^{\circ}\) angle and \(x\) are same - side interior angles. But wait, no! Wait, the \(127^{\circ}\) angle and \(x\) are actually supplementary. Wait, no, hold on. Wait, the \(127^{\circ}\) angle and \(x\) are same - side interior angles. The sum of same - side interior angles is \(180^{\circ}\). So \(x = 180 - 127\).

Step2: Calculate the value of \(x\)

$$x=180 - 127=53$$

Answer:

angle pair is same - side interior angles
\(x = 53\) degrees