QUESTION IMAGE
Question
given: overline{tu} parallel overline{xw}
prove: xw = 8
which step is missing?
a. statement: \frac{xw}{ut} = \frac{vw}{xv} reason: corresponding sides of similar triangles are proportional.
b. statement: \frac{xw}{ut} = \frac{xv}{wv} reason: corresponding sides of similar triangles are proportional.
c. statement: \frac{xw}{ut} = \frac{uv}{wv} reason: corresponding sides of similar triangles are proportional.
d. statement: \frac{xw}{ut} = \frac{uv}{xv} reason: corresponding sides of similar triangles are proportional.
statements | reasons
--- | ---
overline{tu} parallel overline{xw} | given
angle utv cong angle xwv | alternate angles theorem
angle tvu cong angle wvx | vertical angles theorem
\triangle tvu sim \triangle wvx | aa
? | ?
\frac{xw}{14} = \frac{4}{7} | substitution property of equality
7(xw) = 56 | cross product
xw = 8 | division property of equality
Step1: Recall Similar Triangles Property
Since \(\triangle TVU \sim \triangle WVX\) (by AA similarity), corresponding sides of similar triangles are proportional. So, the ratio of corresponding sides should be equal. The sides \(TU\) and \(XW\) are corresponding, and \(TV\) and \(WV\) are corresponding? Wait, no, looking at the diagram, \(TU = 14\)? Wait, no, the length from \(T\) to \(U\) is 14? Wait, the diagram has \(TV = 7\)? Wait, no, the given lengths: \(TX\) is 4? Wait, no, the diagram: \(T\) to \(V\) to \(W\)? Wait, no, the lines: \(\overline{TU} \parallel \overline{XW}\), so \(\triangle TVU \sim \triangle WVX\) (AA, since \(\angle UTV \cong \angle XWV\) (alternate interior angles) and \(\angle TVU \cong \angle WVX\) (vertical angles)). So corresponding sides: \(TV\) corresponds to \(WV\), \(VU\) corresponds to \(VX\), and \(TU\) corresponds to \(XW\)? Wait, no, maybe \(TV\) and \(WX\)? Wait, no, let's check the sides. The length of \(TU\) is 14, \(TV\) is 7? Wait, the diagram: \(T\) to \(U\) is 14, \(T\) to \(V\) is 7? Wait, the segment from \(T\) to \(V\) is 7, and from \(V\) to \(U\) is 14? No, maybe \(TV = 7\), \(TU = 14\) (so \(TV\) is part of \(TU\), with \(V\) between \(T\) and \(U\)), and \(TX = 4\), with \(V\) between \(T\) and \(X\)? Wait, no, the key is that for similar triangles \(\triangle TVU\) and \(\triangle WVX\), the ratio of \(TV\) to \(WV\) should equal the ratio of \(TU\) to \(XW\). Wait, \(TV = 7\), \(WV\) – wait, no, the missing step is the proportion of corresponding sides. So the correct proportion is \(\frac{XW}{TU}=\frac{WV}{TV}\)? Wait, no, let's look at the options. The options are about the proportion \(\frac{XW}{TU}=\frac{WV}{TV}\) or \(\frac{XW}{TU}=\frac{XV}{VU}\) or \(\frac{XW}{TU}=\frac{VW}{TV}\) or \(\frac{XW}{TU}=\frac{UV}{XV}\). Wait, the reason is "corresponding sides of similar triangles are proportional". So for \(\triangle TVU \sim \triangle WVX\), the corresponding sides are \(TV\) and \(WV\), \(VU\) and \(VX\), \(TU\) and \(XW\)? No, maybe \(\triangle TVU \sim \triangle XWV\)? Wait, the angles: \(\angle UTV \cong \angle XWV\) (alternate interior angles, since \(TU \parallel XW\)), and \(\angle TVU \cong \angle WVX\) (vertical angles). So \(\triangle TVU \sim \triangle XWV\) by AA. Therefore, corresponding sides: \(TV\) corresponds to \(XW\), \(VU\) corresponds to \(WV\), \(TU\) corresponds to \(XV\)? No, that doesn't make sense. Wait, maybe the correct proportion is \(\frac{XW}{TU}=\frac{WV}{TV}\). Wait, \(TV = 7\), \(TU = 14\), and we need to find \(XW\). So if \(\frac{XW}{TU}=\frac{WV}{TV}\), but \(WV\) – wait, the length from \(W\) to \(V\) – wait, the diagram has \(TX = 4\)? Wait, no, the given length: \(TX\) is 4? Wait, the problem is to prove \(XW = 8\). Let's see the steps. After proving similarity, the next step is the proportion. The correct proportion for similar triangles \(\triangle TVU\) and \(\triangle WVX\) (or \(\triangle TVU\) and \(\triangle XWV\)) should have corresponding sides. So \(TV = 7\), \(TU = 14\), and let's say \(WV = 4\)? Wait, no, the diagram: \(X\) to \(W\) is what we need to find, \(T\) to \(U\) is 14, \(T\) to \(V\) is 7, and \(X\) to \(V\) is 4? Wait, maybe \(XV = 4\), \(TV = 7\), \(TU = 14\). So for \(\triangle TVU \sim \triangle XWV\), the ratio of \(XV\) to \(TV\) equals \(XW\) to \(TU\)? No, this is getting confusing. Let's look at the options. The reason is "corresponding sides of similar triangles are proportional", so the statement should be the correct proportion. The correct proportion for \(\triangle TVU \sim \triangle WVX\) (or whatev…
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C. Statement: \(\frac{XW}{TU}=\frac{WV}{TV}\) Reason: Corresponding sides of similar triangles are proportional.