Question

it is given that ( k ) is the midpoint of ( overline{sb} ), so ( overline{sk} cong overline{kb} ) by the. it is given that ( overline{hk} parallel overline{wb} ), so ( angle wbk cong angle hks ) by the. it is also given that ( overline{hk} cong overline{wb} ). therefore, ( \triangle hks cong \triangle wbk ) by

Explanation:

Step1: Mid - point definition

By the definition of a mid - point, if \(K\) is the mid - point of \(\overline{SB}\), then \(\overline{SK}\cong\overline{KB}\).

Step2: Corresponding angles (parallel lines)

Since \(\overline{HK}\parallel\overline{WB}\), by the corresponding angles postulate, \(\angle WBK\cong\angle HKS\).

Step3: SAS (Side - Angle - Side) congruence

We have \(\overline{SK}\cong\overline{KB}\), \(\angle WBK\cong\angle HKS\), and \(\overline{HK}\cong\overline{WB}\). By the Side - Angle - Side (SAS) congruence criterion, \(\triangle HKS\cong\triangle WBK\).

Answer:

1. Definition of mid - point
2. Corresponding angles postulate
3. SAS (Side - Angle - Side) congruence criterion