Question

the given jar contains yellow (y), blue (b), and red (r) balls. anne randomly chooses a single ball from the can shown here. find the odds against the event. yellow (y) state the odds against yellow in lowest terms. the odds against yellow are \boxed{} to \boxed{}. (type whole numbers.)

Explanation:

Step1: Count total, yellow, non - yellow balls

First, count the total number of balls. From the jar: red (R) balls: let's count, first row 1 R, second row 2 R, third row 1 R, so total R = 1 + 2+1 = 4. Blue (B) balls: first row 2 B, third row 2 B, so total B = 2 + 2 = 4. Yellow (Y) balls: first row 1 Y, second row 1 Y, third row 1 Y, so total Y = 3. Total balls = 4 (R)+4 (B)+3 (Y)=11. Non - yellow balls = total - yellow = 11 - 3 = 8.

Step2: Calculate odds against yellow

Odds against an event = number of non - favorable outcomes : number of favorable outcomes. For odds against yellow, non - favorable (not yellow) is 8, favorable (yellow) is 3. So odds against yellow are 8 to 3.

Answer:

The odds against yellow are $\boldsymbol{8}$ to $\boldsymbol{3}$.