Question

give the center and radius of the circle described by the equation and graph the equation. use the graph to identify the domain and range.
$(x + 3)^{2}+(y + 5)^{2}=4$
the center is
(type an ordered pair. simplify your answer.)

Explanation:

Step1: Recall the standard form of a circle's equation

The standard form of a circle's equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center and \(r\) is the radius.

Step2: Rewrite the given equation in the standard form

Given \((x + 3)^2+(y + 5)^2=4\), we can rewrite it as \((x-(-3))^2+(y-(-5))^2 = 2^2\).

Answer:

The center is \((-3,-5)\)