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geometry: ---- exit ticket week 17 1) find the h in the proportion \\(\…

Question

geometry: ---- exit ticket week 17

  1. find the h in the proportion \\(\frac{1.7}{h} = \frac{25}{40}\\) (show your work and round your answer to the nearest tenth)

Explanation:

Step1: Cross - multiply the proportion

To solve the proportion \(\frac{1.7}{h}=\frac{25}{40}\), we use cross - multiplication. Cross - multiplication means that if \(\frac{a}{b}=\frac{c}{d}\), then \(a\times d = b\times c\). So for \(\frac{1.7}{h}=\frac{25}{40}\), we get \(25\times h=1.7\times40\).

Step2: Calculate the right - hand side

First, calculate \(1.7\times40\). \(1.7\times40 = 68\). So our equation becomes \(25h = 68\).

Step3: Solve for h

To solve for \(h\), we divide both sides of the equation \(25h = 68\) by 25. So \(h=\frac{68}{25}\).

Step4: Calculate the value and round

\(\frac{68}{25}=2.72\). Rounding \(2.72\) to the nearest tenth, we look at the hundredth place. The digit in the hundredth place is 2, which is less than 5, so we round down. So \(h\approx2.7\).

Answer:

\(h\approx2.7\)