Question

genetics assessment name

1. using this punnett square above, answer the following questions.

a. what genotype are the a father and mother in this punnett square? (homozygous dominant, homozygous recessive or heterozygous)
b. what is the probability that the offspring will be homozygous dominant?
c. what is the probability the offspring will be homozygous recessive?
d. what is the probability that the offspring will be heterozygous?
e. if a is dominant for dimples, and a is recessive for no dimples, what is the probability the child will have dimples.

1. using the trait of \free earlobes\ (e) and \attached earlobes\ (e), design your own punnett square. make you father heterozygous and your mother homozygous recessive. what probability of the child having attached earlobes?

Explanation:

Step1: Analyze the parents' genotypes

The father has the genotype \(Aa\) (heterozygous) and the mother has the genotype \(Aa\) (heterozygous).

Step2: Calculate probabilities for each genotype

• Homozygous dominant (\(AA\)): There is 1 out of 4 possible combinations (\(AA\)), so the probability is \(\frac{1}{4}\) or \(25\%\).
• Homozygous recessive (\(aa\)): There is 1 out of 4 possible combinations (\(aa\)), so the probability is \(\frac{1}{4}\) or \(25\%\).
• Heterozygous (\(Aa\)): There are 2 out of 4 possible combinations (\(Aa\)), so the probability is \(\frac{2}{4}=\frac{1}{2}\) or \(50\%\).
• For dimples (dominant trait): The genotypes \(AA\) and \(Aa\) will show the dominant trait. There are 3 out of 4 combinations (\(AA\), \(Aa\), \(Aa\)), so the probability is \(\frac{3}{4}\) or \(75\%\).

Answer:

a. Father: Heterozygous (\(Aa\)), Mother: Heterozygous (\(Aa\))
b. \(25\%\)
c. \(25\%\)
d. \(50\%\)
e. \(75\%\)