Question

a gamete from an individual pea plant with the genotype eeffgg is likely to have which genotype?
a. efg
b. efg
c. eeffgg
d. eeffgg

Explanation:

Step1: Recall Gamete Formation

Gametes are formed via meiosis, where alleles segregate. For a genotype \( EE Ff Gg \):

• \( E \) is homozygous, so only \( E \) is in gametes.
• \( Ff \) segregates into \( F \) or \( f \).
• \( Gg \) segregates into \( G \) or \( g \).

Step2: Analyze Each Option

• Option A: Has \( e \) (but parent has \( EE \), so no \( e \)) → Eliminate.
• Option B: \( E \) (from \( EE \)), \( F \) (from \( Ff \)), \( G \) (from \( Gg \)) → Valid combination.
• Option C: Has two \( E \), two \( f \), two \( g \) (gametes are haploid, so too many alleles) → Eliminate.
• Option D: Same as parent genotype (gametes are haploid, not diploid) → Eliminate.

Answer:

B. EFG