Question

the functions f and g are defined as follows.
$f(x) = -3x + 2$ $g(x) = 2x^2 - 3x$
find $f(4)$ and $g(-6)$.
simplify your answers as much as possible.
$f(4) = \square$
$g(-6) = \square$

Explanation:

Step1: Calculate \( f(4) \)

Substitute \( x = 4 \) into \( f(x) = -3x + 2 \).
\( f(4) = -3(4) + 2 \)
\( = -12 + 2 \)
\( = -10 \)

Step2: Calculate \( g(-6) \)

Substitute \( x = -6 \) into \( g(x) = 2x^2 - 3x \).
\( g(-6) = 2(-6)^2 - 3(-6) \)
\( = 2(36) + 18 \)
\( = 72 + 18 \)
\( = 90 \)

Answer:

\( f(4) = -10 \)
\( g(-6) = 90 \)