Question

the functions f and g are defined as follows. $f(x)=2x^{3}+6$ $g(x)= - 3x + 2$. find $f(-3)$ and $g(7)$. simplify your answers as much as possible. $f(-3)=square$ $g(7)=square$

Explanation:

Step1: Substitute x = -3 into f(x)

$f(-3)=2(-3)^{3}+6$

Step2: Calculate $(-3)^{3}$

$(-3)^{3}=(-3)\times(-3)\times(-3)= - 27$

Step3: Calculate f(-3)

$f(-3)=2\times(-27)+6=-54 + 6=-48$

Step4: Substitute x = 7 into g(x)

$g(7)=-3\times7 + 2$

Step5: Calculate -3×7

$-3\times7=-21$

Step6: Calculate g(7)

$g(7)=-21+2=-19$

Answer:

$f(-3)=-48$
$g(7)=-19$