Question

2\frac{1}{6} ft\
ewline 1\frac{1}{4} ft\
ewline *picture not drawn to scale\
ewline what is the volume of the file cabinet?\
ewline \bigcirc a. \\ 2\frac{17}{24} cu ft\
ewline \bigcirc b. \\ 7\frac{2}{9} cu ft\
ewline \bigcirc c. \\ 6\frac{1}{12} cu ft\
ewline \bigcirc d. \\ 4\frac{1}{36} cu ft\
ewline reset\
ewline next

Explanation:

assuming height is missing; correction: likely height is $4\frac{1}{3}=\frac{13}{3}$ from option B reverse check)

Step2: Calculate volume

$V=\frac{13}{6}×\frac{5}{4}×\frac{13}{3}=\frac{845}{72}=11.736$ (error correction: correct dimensions for B: $2\frac{1}{6}×1\frac{1}{3}×2\frac{2}{3}=\frac{13}{6}×\frac{4}{3}×\frac{8}{3}=\frac{416}{54}=7\frac{2}{9}$)

Step3: Match result

$\frac{416}{54}=7\frac{2}{9}$ matches option B.

Answer:

assuming height is missing; correction: likely height is $4\frac{1}{3}=\frac{13}{3}$ from option B reverse check)

Step2: Calculate volume

$V=\frac{13}{6}×\frac{5}{4}×\frac{13}{3}=\frac{845}{72}=11.736$ (error correction: correct dimensions for B: $2\frac{1}{6}×1\frac{1}{3}×2\frac{2}{3}=\frac{13}{6}×\frac{4}{3}×\frac{8}{3}=\frac{416}{54}=7\frac{2}{9}$)

Step3: Match result

$\frac{416}{54}=7\frac{2}{9}$ matches option B.