Question

7 four students took turns pushing a box. the table below shows the forces they exerted on the box, the distances they pushed it, and the amount of time they pushed it. which two students did the same amount of work? a students w and x

Explanation:

Step1: Recall work - formula

The work formula is $W = F\times d$, where $W$ is work, $F$ is force and $d$ is distance.

Step2: Calculate work for student W

For student W, $F = 10\ N$ and $d = 4\ m$. So $W_W=F\times d=10\times4 = 40\ J$.

Step3: Calculate work for student X

For student X, $F = 5\ N$ and $d = 8\ m$. So $W_X=F\times d=5\times8 = 40\ J$.

Step4: Calculate work for student Y

For student Y, $F = 5\ N$ and $d = 12\ m$. So $W_Y=F\times d=5\times12 = 60\ J$.

Step5: Calculate work for student Z

For student Z, $F = 1\ N$ and $d = 14\ m$. So $W_Z=F\times d=1\times14 = 14\ J$.

Answer:

A. students W and X