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Question
four interior angles of a pentagon measure 156°, 72°, 98°, and 87°. what is the measure of the final interior angle? 108° 127° 150° 487°
Step1: Calculate the sum of interior angles of a pentagon
The formula for the sum of interior angles of a polygon is \((n - 2)\times180^{\circ}\), where \(n\) is the number of sides. For a pentagon, \(n = 5\), so the sum is \((5 - 2)\times180^{\circ}=540^{\circ}\).
Step2: Find the measure of the unknown angle
Let the unknown angle be \(x\). We know that \(156^{\circ}+72^{\circ}+98^{\circ}+87^{\circ}+x = 540^{\circ}\). First, calculate the sum of the known angles: \(156 + 72+98 + 87=413\). Then, \(x=540 - 413 = 127^{\circ}\).
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\(127^{\circ}\) (the second option)