Question

formula 5 points
the voltage, v, required for a circuit is given by ( v=sqrt{pr} ), where p is the power in watts and r is the resistance in ohms. find the volts needed to light a 6 - watt bulb with a resistance of 80 ohms.
round your answer to the nearest volt. do not include units in your answer.
answer

Explanation:

Step1: Substitute values into formula

Given \(P = 6\) watts and \(R=80\) ohms. Substitute into \(V=\sqrt{PR}\), so \(V = \sqrt{6\times80}\).

Step2: Calculate the product inside the square - root

\(6\times80=480\), so \(V=\sqrt{480}\).

Step3: Simplify the square - root

\(\sqrt{480}=\sqrt{16\times30}=4\sqrt{30}\approx4\times5.477 = 21.908\).

Step4: Round to the nearest volt

Rounding \(21.908\) to the nearest volt gives \(22\).

Answer:

\(22\)