Question

2 formula 1 point a spring is stretched a distance of 0.53 meters and exerts a spring force with a magnitude of 42 newtons. what must be the spring constant? answer

Explanation:

Step1: Recall Hooke's Law

Hooke's Law is \(F = kx\), where \(F\) is the force, \(k\) is the spring constant, and \(x\) is the displacement.

Step2: Solve for \(k\)

Rearrange the formula to \(k=\frac{F}{x}\). Substitute \(F = 42\space N\) and \(x=0.53\space m\). So \(k=\frac{42}{0.53}\).

Step3: Calculate the value

\(k=\frac{42}{0.53}\approx 79.25\space N/m\)

Answer:

\(79.25\space N/m\)