Question

if a force of 250 n acts on a 50 kg object for 10 seconds, and the object starts with a velocity of 2 m/s, what is its final velocity?

Explanation:

Step1: Calculate acceleration

Using Newton's second law \(F = ma\), so \(a=\frac{F}{m}\).
Given \(F = 250\space N\) and \(m = 50\space kg\), then \(a=\frac{250}{50}=5\space m/s^{2}\).

Step2: Use the kinematic equation

The kinematic equation is \(v = u+at\).
Given \(u = 2\space m/s\), \(a = 5\space m/s^{2}\), and \(t = 10\space s\).
Substitute the values: \(v=2 + 5\times10\).
\(v=2+50\).

Answer:

\(52\space m/s\)