Question

the following rational equation has denominators that contain variables. for this equation, a. write the value or values of the variable that make a denominator zero. these are the restrictions on the variable. b. keeping the restrictions in mind, solve the equation.\\(\frac{2}{9x + 27}=\frac{6}{x + 3}-\frac{4}{9}\\)\
a. what is/are the value or values of the variable that make(s) the denominators zero?\
x = \\(\square\\)\
(simplify your answer. use a comma to separate answers as needed.)

Explanation:

Step1: Factor first denominator

$9x+27=9(x+3)$

Step2: Find zero denominators

Set $x+3=0$ → $x=-3$

Answer:

$x=-3$