Question

the following data represent the monthly cell phone bill for a persons phone for six randomly selected months.
\\$35.28, \\$42.09, \\$39.45, \\$38.99, \\$43.39, \\$40.26
compute the mean, median, and mode phone bill.

the mean phone bill is \\$ (round to the nearest cent as needed.)

Explanation:

⚡ Using what you learned: mean (arithmetic average) · 🆕 New: Median and Mode
Finding the middle value and the most frequent value in a dataset.

Step 1: Calculate the Mean

To find the mean, sum all the values and divide by the total number of values (\(n = 6\)):

$$ \text{Sum} = 35.28 + 42.09 + 39.45 + 38.99 + 43.39 + 49.26 = 248.46 $$

$$ \text{Mean} = \frac{248.46}{6} = 41.41 $$

Step 2: Calculate the Median

To find the median, first arrange the data in ascending order:

$$ 35.28, \quad 38.99, \quad 39.45, \quad 42.09, \quad 43.39, \quad 49.26 $$

Since there is an even number of observations (\(n = 6\)), the median is the average of the two middle values (the 3rd and 4th values):

$$ \text{Median} = \frac{39.45 + 42.09}{2} = \frac{81.54}{2} = 40.77 $$

Step 3: Identify the Mode

The mode is the value that occurs most frequently in the dataset.

Looking at the ordered data:

$$ 35.28, \quad 38.99, \quad 39.45, \quad 42.09, \quad 43.39, \quad 49.26 $$

Each value occurs exactly once. Therefore, there is no mode.

Answer:

• Mean: \(41.41\)
• Median: \(40.77\)
• Mode: No mode