Question

if five of the exterior angles of a convex hexagon measure 54°, 58°, 60° 74°, and 79°, find the measure of the sixth exterior angle. degrees question 21 1 pts what is the sum of the exterior angles of a quadrilateral? sum = degrees

Explanation:

Step1: Recall the sum of exterior angles of a polygon

The sum of the exterior angles of any convex polygon is \(360^{\circ}\).

Step2: Calculate the sum of the five given exterior angles

\(54^{\circ}+ 58^{\circ}+60^{\circ}+74^{\circ}+79^{\circ}=325^{\circ}\)

Step3: Find the measure of the sixth exterior angle

Let the sixth exterior angle be \(x\). Then \(x = 360^{\circ}-325^{\circ}\)

Step1: Recall the sum of exterior angles of a polygon

The sum of the exterior angles of any convex polygon is \(360^{\circ}\). A quadrilateral is a polygon.

Answer:

\(35\)