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Question
first factor into intercept form. then graph the parabola (do not place any dots) and fill in the blanks about the vertex, any intercepts, the domain, and range. enter intercepts as ordered pairs, aka points. y = 2x^2 + 8x + 6 equation in factored form
Step1: Factor out the GCF
First, factor out the greatest - common factor of the quadratic expression $y = 2x^{2}+8x + 6$. The GCF of 2, 8, and 6 is 2. So, $y=2(x^{2}+4x + 3)$.
Step2: Factor the quadratic inside the parentheses
We need to find two numbers that multiply to 3 and add up to 4. The numbers are 1 and 3. So, $x^{2}+4x + 3=(x + 1)(x+3)$. Then the factored form of the equation is $y = 2(x + 1)(x + 3)$.
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$y = 2(x + 1)(x + 3)$