Question

find the zeros for the following polynomial function and give the multiplicity for each zero. state whether the graph crosses the x - axis, or touches the x - axis and turns around, at each zero.
f(x)=2(x - 4)(x + 6)^3
the zero(s) of f is, are .
(use a comma to separate answers as needed.)

Explanation:

Step1: Set the function equal to zero

$2(x - 4)(x + 6)^3=0$

Step2: Use the zero - product property

If $ab = 0$, then $a = 0$ or $b = 0$. So we set $x-4=0$ and $(x + 6)^3=0$.
For $x-4=0$, we get $x = 4$.
For $(x + 6)^3=0$, we get $x=-6$.

Answer:

$4,-6$