QUESTION IMAGE
Question
find the x-intercept of each line defined below and compare their values.
equation of line a:
$y + 1 = -(x - 8)$
select values from line b:
| x | y |
| -2 | 1 |
| -1 | 0 |
| 0 | -1 |
| 1 | -2 |
answer attempt 1 out of 2
the x-intercept of line a is \boxed{} and the x-intercept of line b is \boxed{}. therefore the x-intercept of line a is \underline{\hspace{1cm}} the x-intercept of line b.
Step1: Find x-intercept of Line A
To find the x-intercept, set \( y = 0 \) in the equation of Line A: \( y + 1 = -(x - 8) \).
Substitute \( y = 0 \): \( 0 + 1 = -(x - 8) \)
Simplify: \( 1 = -x + 8 \)
Subtract 8 from both sides: \( 1 - 8 = -x \)
\( -7 = -x \)
Multiply both sides by -1: \( x = 7 \)
Step2: Find x-intercept of Line B
The x-intercept occurs where \( y = 0 \). From the table of Line B, when \( y = 0 \), \( x = -1 \).
Step3: Compare the x-intercepts
Line A's x-intercept is 7, Line B's is -1. Since \( 7 > -1 \), Line A's x-intercept is greater than Line B's.
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The \( x \)-intercept of Line A is \( 7 \) and the \( x \)-intercept of Line B is \( -1 \). Therefore the \( x \)-intercept of Line A is greater than the \( x \)-intercept of Line B.