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find the vertex. f(x) = 9(x - 3)^2 - 5 (?, )

Question

find the vertex.
f(x) = 9(x - 3)^2 - 5
(?, )

Explanation:

Step1: Recall vertex form of parabola

The vertex form of a quadratic function is \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

Step2: Identify h and k from given function

Given \( f(x) = 9(x - 3)^2 - 5 \), comparing with \( f(x) = a(x - h)^2 + k \), we have \( h = 3 \) and \( k = -5 \).

Answer:

\((3, -5)\)