Question

find ve (assume a stiff bias circuit).
40v
10 kω
820 ω
1.8 kω
150 ω
answer:

Explanation:

Step1: Calculate base voltage $V_B$

$V_B = V_{CC} \cdot \frac{R_2}{R_1 + R_2} = 40V \cdot \frac{1.8k\Omega}{10k\Omega + 1.8k\Omega} \approx 40V \cdot 0.1525 = 6.1V$

Step2: Calculate emitter voltage $V_E$

$V_E = V_B - V_{BE} \approx 6.1V - 0.7V = 5.4V$ (assuming $V_{BE}=0.7V$ for silicon transistor)

Answer:

5.4V