Question

find the value of the variables in the given figure.
$y = square$
$x = square$
$(7x - 4)^{circ}$
$(2y + 6)^{circ}$
$(6x + 2)^{circ}$

Explanation:

Step1: Use vertical - angles property

Vertical angles are equal. So, \(7x - 4=6x + 2\)

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Step2: Substitute \(x = 6\) into \(2y+6\)

Since \(7x - 4\) and \(2y + 6\) are vertical angles (or use parallel - line properties if lines are parallel, here assume vertical - angles based on figure structure). Substitute \(x = 6\) into \(7x-4\): \(7\times6-4=38\). Then \(2y+6 = 38\)

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Answer:

\(x = 6,y = 16\)