find the value of c. pythagorean theorem: (a^{2}+b^{2}=c^{2})

$find the value of c. pythagorean theorem: (a^{2}+b^{2}=c^{2})$

Let $a = 9$ and $b = 10$.

$c^{2}=a^{2}+b^{2}=9^{2}+10^{2}=81 + 100=181$.

$c=\sqrt{181}\approx 13.45$ ft.

$c=\sqrt{181}\text{ ft}\approx13.45\text{ ft}$