Question

find the value of c. pythagorean theorem: a² + b² = c² 4 m 1 m c = √?

Explanation:

Step1: Identify a and b

Let $a = 4$ and $b = 1$.

Step2: Apply Pythagorean theorem

According to $a^{2}+b^{2}=c^{2}$, we substitute $a$ and $b$ values: $c^{2}=4^{2}+1^{2}$.
Calculate $4^{2}+1^{2}$:
$4^{2}=16$, $1^{2} = 1$, so $4^{2}+1^{2}=16 + 1=17$.
Since $c^{2}=17$, then $c=\sqrt{17}$.

Answer:

$\sqrt{17}$