Question

find the value of c. 9 in 4 in pythagorean theorem: a² + b² = c² c = √?

Explanation:

Step1: Identify values of a and b

Let $a = 4$ and $b=9$.

Step2: Apply Pythagorean theorem

According to $a^{2}+b^{2}=c^{2}$, we substitute $a = 4$ and $b = 9$ into the formula. So $c^{2}=4^{2}+9^{2}=16 + 81$.

Step3: Calculate $c^{2}$ value

$c^{2}=16+81 = 97$.

Step4: Find c

Since $c=\sqrt{c^{2}}$, then $c=\sqrt{97}$.

Answer:

$\sqrt{97}$