Question

find the value of c
c = 10
c = \sqrt{20}
c = \sqrt{52}
c = 8

Explanation:

Step1: Apply Pythagorean theorem

For a right - triangle, \(c^{2}=a^{2}+b^{2}\). Given \(a = 4\) and \(b = 6\).

Step2: Substitute values

\(c^{2}=4^{2}+6^{2}\)
\(c^{2}=16 + 36\)

Step3: Calculate sum

\(c^{2}=52\)

Answer:

\(c^{2}=52\) (corresponding to the orange box \(c = \sqrt{52}\), since \(c^{2}=(\sqrt{52})^{2}=52\))