Question

find the terminal point (p(x,y)) on the unit circle determined by the given value of (t). (t = \frac{3pi}{2}) (p(x,y)=(quad)) resources read it

Explanation:

Step1: Recall unit - circle formulas

For a unit circle \(x = \cos t\) and \(y=\sin t\).

Step2: Substitute \(t=\frac{3\pi}{2}\) into \(x = \cos t\)

\(x=\cos(\frac{3\pi}{2}) = 0\)

Step3: Substitute \(t = \frac{3\pi}{2}\) into \(y=\sin t\)

\(y=\sin(\frac{3\pi}{2})=- 1\)

Answer:

\((0,-1)\)