QUESTION IMAGE
Question
find: tan b? the figure is not drawn to scale. right triangle with legs 32 and 24, hypotenuse 40, angle a at the leg 24, angle b at the leg 32 options: some fractions, including 24/32, 32/24, 32/40, 24/40 (exact text may vary due to image clarity)
Step1: Recall tangent definition
In a right triangle, \(\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}\) to \(\theta\).
Step2: Identify sides for \(\angle B\)
For \(\angle B\), opposite side is \(24\), adjacent side is \(32\).
Step3: Calculate \(\tan B\)
\(\tan B = \frac{24}{32}=\frac{3}{4}\) (simplify by dividing numerator and denominator by 8). Wait, wait, no—wait, let's check again. Wait, the right angle is at the vertex with sides 32 (horizontal) and 24 (vertical), hypotenuse 40. So \(\angle B\): the side opposite to \(\angle B\) is 24, adjacent is 32? Wait, no—wait, angle \(B\): let's label the triangle. Let the right angle be \(C\), so \(AC = 24\), \(BC = 32\), \(AB = 40\). Then \(\angle B\) is at vertex \(B\), so the sides: opposite to \(\angle B\) is \(AC = 24\), adjacent is \(BC = 32\)? Wait, no, adjacent to \(\angle B\) is the side forming \(\angle B\) with the hypotenuse, which is \(BC\)? Wait, no, in right triangle, for angle \(B\), the two legs: one is opposite (\(AC\)), one is adjacent (\(BC\)). So \(\tan B=\frac{\text{opposite}}{\text{adjacent}}=\frac{AC}{BC}=\frac{24}{32}=\frac{3}{4}\)? But the options—wait, the options have \(\frac{24}{32}\) simplified? Wait, the options: let's see the image. The options are (from what I can see) \(\frac{24}{32}\) (simplify to \(\frac{3}{4}\)), \(\frac{32}{24}\), \(\frac{32}{40}\), \(\frac{24}{40}\). Wait, no, maybe I mixed up opposite and adjacent. Wait, angle \(B\): the side adjacent to \(B\) is the leg that is part of \(\angle B\) (not the hypotenuse). So \(\angle B\) is between \(BC = 32\) and \(AB = 40\), so the adjacent side is \(BC = 32\), opposite side is \(AC = 24\). Wait, but maybe I had it reversed. Wait, no—let's use SOHCAHTOA correctly. \(\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}\). So for \(\angle B\), the side opposite is \(AC = 24\), adjacent is \(BC = 32\). So \(\tan B=\frac{24}{32}=\frac{3}{4}\), but looking at the options, maybe the options are \(\frac{24}{32}\) (which is \(\frac{3}{4}\) but maybe not simplified). Wait, the options in the image: let's parse the text. The problem is "Find \(\tan B\)". The triangle has legs 32 (horizontal) and 24 (vertical), hypotenuse 40. So \(\angle B\): opposite side is 24, adjacent is 32. So \(\tan B=\frac{24}{32}=\frac{3}{4}\), but the options—wait, maybe I made a mistake. Wait, no, maybe the adjacent is 24 and opposite is 32? Wait, no, let's draw the triangle: right angle at \(C\), so \(C\) is the right angle, \(BC = 32\) (horizontal), \(AC = 24\) (vertical), \(AB = 40\) (hypotenuse). Then \(\angle B\) is at \(B\), so the angle between \(BC\) (32) and \(AB\) (40). So the sides: for \(\angle B\), the opposite side is \(AC = 24\) (opposite to \(B\)), and the adjacent side is \(BC = 32\) (adjacent to \(B\)). So \(\tan B=\frac{24}{32}=\frac{3}{4}\), but the options—wait, the options given (from the image) seem to have \(\frac{24}{32}\) (or simplified), \(\frac{32}{24}\), \(\frac{32}{40}\), \(\frac{24}{40}\). Wait, maybe I flipped opposite and adjacent. Wait, if \(\angle B\) is at \(B\), then the adjacent side is \(AB\)'s adjacent? No, no. Wait, maybe the triangle is labeled differently. Wait, maybe the horizontal leg is \(AC = 32\), vertical leg \(BC = 24\)? Wait, the image shows "32" on the horizontal, "24" on the vertical, hypotenuse "40". So angle \(A\) is at the bottom, angle \(B\) at the top. So for angle \(B\), the opposite side is the horizontal leg (32? No, vertical leg is 24, horizontal is 32. Wait, no—if angle \(B\) is at the top, then the side opposite to \(B\) is the horizontal leg (32), and ad…
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\(\frac{24}{32}\) (or \(\frac{3}{4}\), depending on simplification; the option with 24/32)